In this part you do not have to sketch the graph and you may even be given the sketch of the graph to start with. For a quadratic equation of the form \(y = k{(x - a)^2} + b\), the following ...

“The vertex is at x = 4,” she said, “because the roots are x = 1 and x = 7, and the roots are symmetric about the vertex.” She used the fact that the parabola is the graph of a quadratic polynomial, ...

Spoiler alert: The vertex can be anywhere on the perpendicular bisector of those two points. (Neat!) Now, suppose the two distinct points are anywhere on the coordinate plane.

Save guides, add subjects and pick up where you left off with your BBC account. A quadratic graph is produced when you have an equation of the form \(y = ax^2 + bx + c\), where \(b\) and \(c\) can ...