and acceleration = velocity change ÷ time. To find the distance travelled, look at the area under the graph. In the first 10 seconds this is the area of the triangle, ½ × 10 s × 40 m/s = 200 m.

time and another graph for position vs ... Actually, let me change the problem. If the acceleration part is just around 5 minutes total out of 45 minutes, the curved part of the position graph ...

Save guides, add subjects and pick up where you left off with your BBC account. The gradient of a velocity-time graph at a particular time gives the acceleration of the object at that time.